Students of canoeists trip traveled in three days 102 km.
Second day traveled 15% more than first day and at the third day 9 km over the second day.

How many kilometers traveled each day?

Result

1st d:  28.18 km
2nd d:  32.41 km
3rd d:  41.41 km

#### Solution:

$x+y+z = 102 \ \\ x + \dfrac{100+15}{100} x + \dfrac{100+15}{100} x + 9 = 102 \ \\ \ \\ 3.3 x = 102 - 9 \ \\ \ \\ x = 28.18 \ \text{ km } \ \\$
$y = \dfrac{100+15}{100} x = 32.41 \ \text{ km }$
$z = y+ 9 = 41.41 \ \text{ km }$

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