Fibonacci numbers

If the first three Fibonacci numbers are given as x1 = 1, x2 = 1, and x3 = 2, then what is the least value of n for which x(n) > 500?

Correct answer:

n =  15

Step-by-step explanation:

x1=1 x2=1 x3=x2+x1=1+1=2 x4=x3+x2=2+1=3 x5=x4+x3=3+2=5 x6=x5+x4=5+3=8 x7=x6+x5=8+5=13 x8=x7+x6=13+8=21 x9=x8+x7=21+13=34 x10=x9+x8=34+21=55 x11=x10+x9=55+34=89 x12=x11+x10=89+55=144 x13=x12+x11=144+89=233 x14=x13+x12=233+144=377 x15=x14+x13=377+233=610 x15>500  n=15



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