From city 2

A passenger train left city A for city B in the morning. At the same time, a freight train left city B for city A along the same track. Both trains travelled the entire route at constant speeds. They passed each other on the track at 9:45 a.m. The passenger train reached its destination at 11:45 a.m. and the freight train at 2:15 p.m., both on the same day they departed. What time did they depart?

Result

t = 6:45 hh:mm Wrong answer

Step-by-step explanation:

t1=9:45=9 hr 45 min =9+6045=9.75 hr=9.75 t2=11:45=11 hr 45 min =11+6045=11.75 hr=11.75 t3=14:15=14 hr 15 min =14+6015=14.25 hr=14.25  s1 = v1 (t1t) s2 = v2 (t1t) s1+s2 = s s = v1 (t2t) s = v2 (t3t)  k = v1/v2   v1 (t1t) +  v2 (t1t) = v1 (t2t) = v2 (t3t)  k (t1t) +  (t1t) = k (t2t) = (t3t)   k (t1t) +  (t1t) = k (t2t)  k (t1t) +  (t1t) = (t3t)  k1=3/2=23=1.5 k2=3/2=23=1.5 k>0  k=k2=1.5=23  k (t2t)=(t3t) 1.5 (11.75t)=(14.25t)  0.5t=3.375  t=0.53.375=6.75  t=427=6.75=6:45 hh:mm



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