Distribution 81063

The weight of a loaf of bread should be 900 g. Loaves whose weight differs by more than 30 g from this value must be rejected. Determine the probability that a loaf is rejected if its weight has a normal distribution N(900,40).

Correct answer:

p =  0.4533

Step-by-step explanation:

$$\begin{gathered} m\dots N(900,40) \\ \mu =900\text{g} \\ \sigma =40\text{g} \\ a=\mu -30=900-30=870\text{g} \\ b=\mu +30=900+30=930\text{g} \\ {p}_1=N(a<m<b) \\ {p}_1=0.5467 \\ p=1-p_1=1-0.5467=0.4533 \end{gathered}$$

Use the normal distribution table.

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