Train
A train moves along a track at constant speed v0 for a time t1 = 1.00 h, but then it must stop due to works on the track and waits at the place for a time t2 = 0.50 h. When it gets moving again, its constant speed is only 75% of the original speed v0. The train arrives at the destination with a delay of t4 = 1.50 h, compared to the timetable, which counted with the constant speed v0 during the entire duration of the ride. If the place where the train had to stop were s2 = 45.0 km further in the direction of travel, the delay of the train (compared to the timetable) would be only t5 = 1.00 h.
a) How long was the journey supposed to last (t6) according to the timetable?
b) What was the speed v0 of the train in the first part (planned speed according to the timetable)?
c) What was the total length s of the track?
d) Construct graphs of speed as a function of time in both cases into a common graph.
a) How long was the journey supposed to last (t6) according to the timetable?
b) What was the speed v0 of the train in the first part (planned speed according to the timetable)?
c) What was the total length s of the track?
d) Construct graphs of speed as a function of time in both cases into a common graph.
Final Answer:
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