# Dance group

The dance group formed groups of 4, 5, and 6 members. Always one dancer remains. How many dancers were there in the whole group?

Result

n =  61

#### Solution:

$4=2^2 \ \\ 5 \ ... \ prime number \ \\ 6=2 \cdot 3 \ \\ LCM(4, 5, 6)=2^2 \cdot 3 \cdot 5=60 \ \\ \ \\ n=LCM(4,5,6)+1=61$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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