Parachutists

Parachutists during freefall firstly held in groups of 4, then of 6, then 9, 12 and finally of 18 members. How many parachutists jump at least should be, if at each group must all be involved.

Correct result:

n =  36

Solution:

4=22 6=2⋅3 9=32 12=22⋅3 18=2⋅32 LCM(4,6,9,12,18)=22⋅32=36  n=LCM(4,6,9,12,18)=364=2^2 \ \\ 6=2 \cdot 3 \ \\ 9=3^2 \ \\ 12=2^2 \cdot 3 \ \\ 18=2 \cdot 3^2 \ \\ LCM(4, 6, 9, 12, 18)=2^2 \cdot 3^2=36 \ \\ \ \\ n=LCM(4,6,9,12,18)=36

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