Operation 82150

In 24 hours, the engine consumes 346 I of gasoline. How many liters does it consume in 126 hours of operation?

Correct answer:

V2 =  1816.5 l

Step-by-step explanation:

V1=346 l t1=24 h t2=126 h  V2:t2 = V1:t1  V2=t1t2 V1=24126 346=24126 346=2443596=1816.5 l

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