Double-return 82524

Calculate at what distance from the axis of rotation a force of 60N acts on one side of a double-return lever; if a force of 180N acts on the other side at a distance of 1 meter from the axis of rotation, the lever is in equilibrium.

Correct answer:

x₁ =  3 m

Step-by-step explanation:

$$\begin{gathered} F_1=60\text{N} \\ {F}_2=180\text{N} \\ {x}_2=1\text{m} \\ {M}_1=M_2 \\ {M}_1=F_1{x}_1 \\ {M}_2=F_2{x}_2 \\ {F}_1{x}_1=F_2{x}_2 \\ {x}_1=x_2\cdot \frac{F_2}{F_1}=1\cdot \frac{180}{60}=\frac{1\cdot 180}{60}=\frac{180}{60}=3\text{m} \end{gathered}$$

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