One three

We throw two dice. What is the probability that max one three falls?

Result

p =  0.972

Solution:

p=6⋅ 6−16⋅ 6=3536≐0.9722≐0.972p=\dfrac{ 6 \cdot \ 6-1 }{ 6 \cdot \ 6 }=\dfrac{ 35 }{ 36 } \doteq 0.9722 \doteq 0.972

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