Meeting of two airplanes

Two airplanes took off simultaneously from two airports 500 km apart, flying toward each other. One flies at a speed of 480 km/h, the other at 720 km/h. How long after takeoff will they meet and what distance will the first airplane fly?
a) If there is no wind
b) If wind blows throughout the entire space at 80 km/h in the direction of the second airplane's flight
c) If the wind blows at the same speed in the opposite direction.

Final Answer:

t1 =  0.4167 h
t2 =  0.4167 h
t3 =  0.4167 h

Step-by-step explanation:

s=500 km v1=480 km/h v2=720 km/h  v=v1+v2=480+720=1200 km/h  t1=s/v=500/1200=0.4167 h
Δv=80 km/h v3=v1Δv=48080=400 km/h v4=v2+Δv=720+80=800 km/h  v5=v3+v4=400+800=1200 km/h  t2=v5s=1200500=0.4167 h
t3=t2=0.4167=0.4167 h



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geometryarithmeticUnits of physical quantitiesthemes, topicsGrade of the word problem

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