Garden 3

A garden pool in the shape of a cylinder with a base diameter of 300 cm contains 25 hectolitres of water. How deep is it if the water reaches 10 cm below the rim of the pool?

Final Answer:

h =  0.4537 m

Step-by-step explanation:

$$\begin{gathered} D=300\text{cm}\to \text{m}=300:100\text{m}=3\text{m} \\ V=25\text{hl}\to {\text{m}}^3=25:10{\text{m}}^3=2.5{\text{m}}^3 \\ {h}_1=10\text{cm}\to \text{m}=10:100\text{m}=0.1\text{m} \\ r=D/2=3/2=\frac{3}{2}=1.5\text{m} \\ {S}_1=\pi \cdot r^2=3.1416\cdot 1.5^2\doteq 7.0686{\text{m}}^2 \\ V=S_1\cdot h_2 \\ {h}_2=V/S_1=2.5/7.0686\doteq 0.3537\text{m} \\ h=h_2+h_1=0.3537+0.1=0.4537\text{m} \end{gathered}$$

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