# Pharmacy

At the pharmacy are in one container 20% solution in the second 50% solution of disinfectant. They need to prepare 4 L of 48-percent solution.

What amount of solution from each container is needed to mix?

Result

x =  0.27 L
y =  3.73 L

#### Solution:

$x+y = 4 \ \\ 0.2x + 0.5 y = 0.48 \cdot 4 \ \\ \ \\ y = 4 - x \ \\ 0.2x + 0.5(4-x) = 0.48 \cdot 4 \ \\ x = \dfrac{ 0.5 - 0.48 }{ 0.3} \cdot 4 = 0.27 \ \text{L}$
$y = 4 - x = 3.73 \ \text{L}$

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