Cinema

How many ways can be divided 11 free tickets to the premiere of "Jáchyme throw it in the machine" between 6 pensioners?

Correct answer:

x =  4368

Step-by-step explanation:

$$\begin{gathered} C_{11}(16)=\left({\displaystyle \genfrac{}{}{0px}{}{16}{11}}\right)={\displaystyle \frac{16!}{11!(16-11)!}}={\displaystyle \frac{16\cdot 15\cdot 14\cdot 13\cdot 12}{5\cdot 4\cdot 3\cdot 2\cdot 1}}=4368 \\ n=6 \\ k=11 \\ x=\left(\genfrac{}{}{0px}{}{n+k-1}{k}\right)=\left(\genfrac{}{}{0px}{}{6+11-1}{11}\right)=4368 \end{gathered}$$

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Showing 4 comments:

Math student

wrong

2 years ago  Like

Math student

shouldn't it be 4368 ( 16 choose 11)

2 years ago  Like

Dr Math

are you sure? Aren't combinations with repetition?

2 years ago  Like

Math student

The answer is 4368. It’s a combination with repetition problem with n=6, r= 11.

2 years ago  Like

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