Dices

We will throw two dice. What is the probability that the ratio between numbers on first and second dice will be 1:2?

Correct result:

p =  0.17 %

Solution:

$p={\displaystyle \frac{2\cdot 3}{6\cdot 6}}={\displaystyle \frac{1}{6}}=0.17\mathrm{\%}$

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