Boat

A force of 300 kg (3000 N) is required to pull a boat up a ramp inclined at 14° with horizontal.

How much does the boat weight?

Result

m =  1240.07 kg

Solution:

F=Gsin14  G=Fsin14=300sin14=1240.07 kgF = G \sin 14 ^\circ \ \\ \ \\ G = \dfrac{F }{ \sin 14 ^\circ } = \dfrac{ 300 }{ \sin 14 ^\circ } = 1240.07 \ \text{kg}



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