Richard's numbers Z8-I-2 2019

Richard was playing with two five-digit numbers. Each consisted of different digits: one number used only odd digits and the other only even digits. After a while, he found that the sum of these two numbers starts with the repeated digit 1 (i.e. begins with 11) and ends with the digit 1, and that their difference starts with the digit 2 and ends with the repeated digit 1 (i.e. ends with 11).
Determine Richard's numbers.

Final Answer:

a =  73591
b =  46280

Step-by-step explanation:

a=73591 b=46280 s=a+b=73591+46280=119871 r=ab=7359146280=27311
b=46280



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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsnumbersthemes, topicsGrade of the word problem

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