# Ravens

The tale of the Seven Ravens were seven brothers, each of whom was born exactly 1.5 years after the previous one. When the eldest of the brothers was 4-times older than the youngest, mother all curse. How old was seven ravens brothers when their mother cursed?

Result

k1 (youngest) =  3
k2 =  4.5
k3 =  6
k4 =  7.5
k5 =  9
k6 =  10.5
k7 (oldest) =  12

#### Solution:

$$\smash{ \frac{ k_1}{ k_7} = \frac{ x }{ 6\cdot 1.5+x } = \frac{ 1} { 4 } \\~\\ 4 x = 6 \cdot 1.5 + x \\~\\x = \frac{ 6\cdot 1.5}{ 4-1} = 3 \\~\\ \\~\\ k_1 = 3 \\~\\k_2 = k_1 + 1.5 = 4.5 \\~\\k_3 = k_2 + 1.5 = 6 \\~\\k_4 = k_3 + 1.5 = 7.5 \\~\\k_5 = k_4 + 1.5 = 9 \\~\\k_6 = k_5 + 1.5 = 10.5 \\~\\k_7 = k_6 + 1.5 = 12 }$$

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