Pythagorean theorem - practice problems - page 2 of 74
A common proof of the Pythagorean Theorem is called the "area proof". To prove the theorem using this method, we can create a square with side length c and two smaller squares with side lengths a and b, as shown in the figure. We can then place the smaller squares next to each other to form a rectangle with area a x b. We can then see that the area of the square with side length c is equal to the sum of the areas of the smaller squares, which is equal to the area of the rectangle. This demonstrates that c2 = a2 + b2, as stated in the theorem.Another proof is Euclidean proof which is based on the Euclidean geometry and construction of a line segment that is c and perpendicular to the line segment of a and b.
Number of problems found: 1464
- A tree 2
A tree is broken at a height of 6 m from the ground and its top touches the ground at a distance of 8 m from the base of the tree. Find the original height of the tree. - Two chords 6
A chord PQ is 10.4 cm long, and its distance from the center of a circle is 3.7 cm. Calculate the length of a second chord RS, which is 4.1 cm from the center of this circle. - A right triangle
A right triangle has legs with lengths of 24 cm and 21 cm if the length of the hypotenuse, in cm, can be written in the form of 3 sqrt(d), then what is the value of d? - A triangle 7
A triangle lot has the dimensions a=15 m, b=10 m, and c=20 m. What is the measure of the angle between the sides of b and c? - South and then east
William walks 16 m south from his house and turns east to walk 63 m to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance did he walk while returning? - In football
In football, the path that a defender must run to tackle the ball carrier is called the path of pursuit. If the ball carrier runs 40 yards to the end zone and the path of pursuit is 45 yards; how far apart were the ball carrier and defender when they star - Mrs. Clarke
Mrs. Clarke is teaching a 5th-grade class. She is standing 40 feet in front of Valeria. Sarah is sitting to Valeria's right. If Sarah and Mrs. Clarke are 50 feet apart, how far apart are Valeria and Sarah? - Three 235
Three houses form a triangular shape. House A is 50 feet from house C and house B is 60 feet from house C. The measure is angle ABC is 45 degrees. Draw a picture and find the distance between A and B. - An isosceles triangle
An altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles. As a result, the altitude cuts the base into two equal segments. The length of the altitude is 18 inches, and the length of the base is 15 in - Piece of a wire
A piece of wire is bent into the shape of a triangle. Two sides have lengths of 24 inches and 21 inches. The angle between these two sides is 55°. What is the length of the third side to the nearest hundredth of an inch? A: The length of the third side is - A ladder 3
A 30 foot ladder is set against the side of a house so that it reaches up 24 feet. If Elizabeth grabs the ladder at its base and pulls it 3 feet farther from the house, how far up the side of the house will the ladder reach now? Round to the nearest tenth - The rhombus (a,d)
Find the area of a rhombus, one side of which measures 20 cm and one diagonal of which is 24 cm. - Parallelogram - right angles
In parallelogram ABCD; AB = 16 cm, BC = 12 cm and diagonal AC = 20 cm. Find the area of the parallelogram. - A lighthouse
A lighthouse overlooks a bay, and it is 77 meters high. From the top, the lighthouse keeper can see a yacht southward at an angle of depression of 32 degrees and another boat eastward at an angle of 25 degrees. What is the distance between the boats? - A tree 3
A tree breaks due to a storm and the broken part bends so that the top of the tree touches the ground at an angle of 30°. The distance from the foot of the tree to the point where the top touches the ground is 8 m. Find the original height of the tree. - ABCD rhombus
ABCD is a rhombus with sides of 10.5 cm. If the length of diagonal AC = 15.8 cm, use the cosine rule to: a. calculate the length of diagonal BD to the nearest centimetre, b. find the angles of the rhombus to the nearest degree. - Grassland and goat
An unfenced piece of grassland is a right triangle ABC with AB = 4 m, BC = 8 m, and AC as the hypotenuse. A goat is tied to a 5-metre rope with its stake at point O, which is 2 m from side AB and 2 m from the extension of side BC beyond corner B. Then: 1. - Two chords 2
The length of one of two chords of a circle is 12 cm. If the chords are 6 cm and 7 cm away from the center of the circle, calculate the length of the second chord. - A baseball
A baseball is hit over a fence that is 325 feet away and 110 feet tall. How far did the ball travel in a straight line when it reached the fence? - Three inscribed objects
A circle is inscribed in a square. An equilateral triangle with side 4√3 is inscribed in that circle. Find the length of the diagonal of the square.
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