Aircrafts

The bomber started at 9:00 from the airport and flew at an average speed of 1850 km/h toward Airfield B, a distance of 3500 km. After evaluating the danger from the airport, B started at 9:45 B towards A fighter at an average speed of 2300 km/h. At what time and at what distance do these two aircraft meet from Airport A?

Final Answer:

t =  10.259 h
s =  2329.2169 km

Step-by-step explanation:

s=v1 (tt1)=1850 (10.2599)=2329.2169 km



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