Airplane 81200

Two points at a distance of 1840 km. An airplane departs from A at 7:00 a.m. and flies at an average speed of 50 km/h faster than another airplane departs from B at 8:00 a.m. At what distance from A do they meet at 9:00?

Correct answer:

x =  1260 km

Step-by-step explanation:

s=1840 t1=9.007.00=2 h t2=9.008.00=1 h  s1+s2=s=1840  (v+50) t1+v t2=s (v+50) 2+v 1=1840  3v=1740  v=31740=580  v=580  v1=v+50=580+50=630 km/h v2=v=580 km/h  x=v1 t1=630 2=1260 km

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