# Blackjack TU160

Bomber Tupolev TU160 started at 9:00 from the airport and flew at an average speed of 1850 km/h toward airfield B distant 3500 km. After evaluating the danger from the airport B started at 9:45 B towards A fighter MIG 29 at an average speed of 2300 km/h. At what time and at what distance from airport A these two aircraft meet?

Result

t = 10:16 h s =  2329.2 km

### Step-by-step explanation:

s=1850(t-9)
3500 = 1850(t-9) + 2300(t-(9+45/60))

s=1850·(t-9)
3500 = 1850·(t-9) + 2300·(t-(9+45/60))

s-1850t = -16650
249000t = 2554500

t = 2554500/249000 = 10.25903614
s = -16650+1850t = -16650+1850 · 10.25903614 = 2329.21686747

s = 2329.216867
t = 1703/166 ≈ 10.259036

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