Three circles of radius 30 cm, 28 cm, and 37 cm are mutually tangent. What is the triangle perimeter whose vertices are the circles' centers?

Correct answer:

o =  190 cm

Step-by-step explanation:

r1=30 cm r2=28 cm r3=37 cm  a=r1+r2=30+28=58 cm b=r2+r3=28+37=65 cm c=r3+r1=37+30=67 cm  o=a+b+c=58+65+67=190=190 cm   Verifying Solution:  o2=2 (r1+r2+r3)=2 (30+28+37)=190 cm o2=o

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