The tractor

The tractor sows an average of 1.5 ha per hour. In how many hours does it sows a rectangular trapezoid field with the bases of 635m and 554m and a longer arm 207m?

Result

t =  7.55 h

Solution:

a=635 n c=554 m b=207 m  h=b2−(a−c)2=2072−(635−554)2≐72 7 m≐190.4941 m  S=a+c2⋅ h=635+5542⋅ 190.4941≐113248.7391 m2  S1=S→ha=S/10000 ha=11.32487 ha  t=S1/1.5=11.3249/1.5≐7.5499≐7.55 ha=635 \ \text{n} \ \\ c=554 \ \text{m} \ \\ b=207 \ \text{m} \ \\ \ \\ h=\sqrt{ b^2 - (a-c)^2 }=\sqrt{ 207^2 - (635-554)^2 } \doteq 72 \ \sqrt{ 7 } \ \text{m} \doteq 190.4941 \ \text{m} \ \\ \ \\ S=\dfrac{ a+c }{ 2 } \cdot \ h=\dfrac{ 635+554 }{ 2 } \cdot \ 190.4941 \doteq 113248.7391 \ \text{m}^2 \ \\ \ \\ S_{1}=S \rightarrow ha=S / 10000 \ ha=11.32487 \ ha \ \\ \ \\ t=S_{1}/1.5=11.3249/1.5 \doteq 7.5499 \doteq 7.55 \ \text{h}

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