The tractor

The tractor sows an average of 1.5 ha per hour. In how many hours does it sows a rectangular trapezoid field with the bases of 635m and 554m and a longer arm 207m?

Correct result:

t =  7.5499 h

Solution:

$$\begin{gathered} a=635\text{ n } \\ c=554\text{ m } \\ b=207\text{ m } \\ h=\sqrt{b^2-(a-c{)}^2}=\sqrt{207^2-(635-554{)}^2}=72\sqrt{7}\text{ m}\doteq 190.4941\text{ m } \\ S={\displaystyle \frac{a+c}{2}}\cdot h={\displaystyle \frac{635+554}{2}}\cdot 190.4941\doteq 113248.7391{\text{m}}^2 \\ {S}_1=S\to \text{ ha}=S\mathrm{/}10000\text{ ha}=113248.7391\mathrm{/}10000\text{ ha}=11.32487\text{ ha } \\ t=S_1\mathrm{/}1.5=11.3249\mathrm{/}1.5=7.5499\text{ h} \end{gathered}$$

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