Square side

Calculate length of side square ABCD with vertex A[0, 0] if diagonal BD lies on line p: -4x -5 =0.

Correct result:

a =  1.77

Solution:

$$\begin{gathered} v(A,BD)={\displaystyle \frac{\mathrm{\mid }-4\cdot 0+\cdot 0-5\mathrm{\mid }}{\sqrt{(-4{)}^2+0^2}}}=1.25 \\ u=\mathrm{\mid }AC\mathrm{\mid }=\mathrm{\mid }BD\mathrm{\mid }=2\cdot v(A,BD)=2.5 \\ u=\sqrt{2}a \\ a=u\mathrm{/}\sqrt{2}=1.77 \end{gathered}$$

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