Isosceles triangle

In an isosceles triangle ABC with base AB; A [3,4]; B [1,6] and the vertex C lies on the line 5x - 6y - 16 = 0. Calculate the coordinates of vertex C.

Correct result:

x =  2
y =  -1

Solution:

x0=3;y0=4 x1=1;y1=6  (xx0)2+(yy0)2=(xx1)2+(yy1)2 5 x6 y16=0  y=(5 x16)/6  (xx0)2+((5 x16)/6y0)2=(xx1)2+((5 x16)/6y1)2 (x+3)2+((5 x16)/64)2=(x1)2+((5 x16)/66)2 x2+6x+9+25/36x2100x/9+400/9=x22x+1+25/36x2130x/9+676/9   6 x+9100 x/9+400/9=2 x+1130 x/9+676/9  102x=204  x=2
y=(5 x16)/6=(5 216)/6=1



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