Vertex of the rectangle

Determine the coordinates of the vertex of the rectangle inscribed in the circle x2+y2 -2x-4y-20=0 if you know that one of its sides lies on the line p: x+2y=0

Final Answer:

A = (-4,2)
B = (4,-2)
C = (6,2)
D = (-2,6)

Step-by-step explanation:

x2+y2 2x4y20=0  (x  1)2 + (y  2)2 = 25 = 52  S=(1,2)  (2y)2+y22 (2y)4y20=0  (2y)2+y22 (2y)4y20=0 5y220=0 5 ...  prime number 0 20=225 GCD(5,0,20)=5  y24=0 y1,2=±4=±2 y1=2 y2=2  x1=2 y1=2 2=4 x2=2 y2=2 (2)=4  A=(x1,y1) A=(4,2)

Our quadratic equation calculator calculates it.

B=(x2,y2) B=(4,2)
q=AS Ay=a Ax+b Sy=a Sx+b  2=a (4)+b 2=a (1)+b  4ab=2 ab=2  Row241 Row1Row2 0.75b=1.5  b=0.751.5=2 a=42+b=42+2=0  a=0 b=2  (w)2+222 (w)4 220=0  (w)2+222 (w)4 220=0 w22w24=0  a=1;b=2;c=24 D=b24ac=2241(24)=100 D>0  w1,2=2ab±D=22±100 w1,2=22±10 w1,2=1±5 w1=6 w2=4  C=(w1, b) C=(6,2)

Our quadratic equation calculator calculates it.

t=BS By=c Bx+d Sy=c Sx+d  4=c (2)+d 2=c (1)+d  2cd=4 cd=2  Row221 Row1Row2 0.5d=0  d=0.50=0 c=24+d=24=2  c=2 d=0  t: x=2  (2)2+v22 (2)4 v20=0  (2)2+v22 (2)4 v20=0 v24v12=0  a=1;b=4;c=12 D=b24ac=4241(12)=64 D>0  v1,2=2ab±D=24±64 v1,2=24±8 v1,2=2±4 v1=6 v2=2  D=(c,v1)  D=(2,6)

Our quadratic equation calculator calculates it.




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geometryalgebraplanimetrybasic operations and conceptsUnits of physical quantitiesGrade of the word problem

 
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