What must be an observer's elevation so that he may see an object on the Earth 536 km away? Assume the Earth to be a smooth sphere with a radius 6378.1 km.

Correct answer:

h =  22482.4 m

Step-by-step explanation:

R=6378.1 km d=536 km  (R+h)2=d2+R2 R+h=d2+R2 h=d2+R2R h=5362+6378.126378.1 h=22482.4 m

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