Pool coating

How many pieces of tiles 25 cm × 15 cm need to coat the bottom and side walls of the pool with bottom dimensions 30 m × 5 m, if the pool can fit up to 271500 liters of water?


n =  7379


V=abc c=Vab=271.5 m3305=1.81 m S1=2515/100/100=0.0375m2  S=305+21.8130+21.815=276.7m2  n=S/S1=276.7/0.0375=7379 V = abc \ \\ c = \dfrac{V}{ab} = \dfrac{ 271.5 \ m^3}{ 30 \cdot 5 } = 1.81 \ m \ \\ S_1 = 25\cdot 15 / 100 / 100 = 0.0375 m^2 \ \\ \ \\ S = 30\cdot 5 + 2\cdot 1.81\cdot 30 + 2\cdot 1.81\cdot 5 = 276.7 m^2 \ \\ \ \\ n = S/S_1 = 276.7/ 0.0375 = 7379 \ \\

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