Division

Three siblings Helena, Oliver and George split the bag with candies on merit in the ratio 6:1:4. How many candies should each get if in bag were 88?

x =  48
y =  8
z =  32

Step-by-step explanation:

$y=1a=8$
$z=4a=32$

6 a + 1 a + 4 a = 88; x= 6 a; y= 1 a ; z= 4 a

6•a + 1•a + 4•a = 88
x= 6•a
y= 1•a
z= 4•a

11a = 88
6a-x = 0
a-y = 0
4a-z = 0

a = 8
x = 48
y = 8
z = 32

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