30-60-90

The longer leg of a 30°-60°-90° triangle measures 5. What is the length of the shorter leg?

Result

x =  2.5

Solution:

sin⁡30∘=x5 x=5⋅sin⁡30∘=2.5\sin 30 ^\circ = \dfrac{x}{ 5} \ \\ x = 5 \cdot \sin 30 ^\circ = 2.5

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