Perpendicular 41811

Calculate the area of a right triangle whose longer perpendicular is six dm shorter than the hypotenuse and three dm longer than the shorter perpendicular.

Correct answer:

S =  158.9423 dm2

Step-by-step explanation:

a = c6 a = 3+b a2+b2 = c2  (c6)2+(a3)2 = c2 (c6)2+((c6)3)2=c2  c230c+117=0  p=1;q=30;r=117 D=q24pr=30241117=432 D>0  c1,2=2pq±D=230±432=230±123 c1,2=15±10.392305 c1=25.392304845 c2=4.607695155  c=c1=25.392325.3923 dm a=c6=25.3923619.3923 dm b=a3=19.3923316.3923 dm  S=2a b=219.3923 16.3923158.9423 dm2   Verifying Solution:  c3=a2+b2=19.39232+16.3923225.3923 dm

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