Right trapezoid

The right trapezoid has bases 3.2 cm and 62 mm long. The shorter leg has a length 0.25 dm. Calculate the lengths of the diagonals and the second leg.

Correct result:

u1 =  6.685 cm
u2 =  4.061 cm
b =  3.905 cm

Solution:

a=62 mm→cm=62/10 cm=6.2 cm c=3.2 cm d=0.25 dm→cm=0.25⋅ 10 cm=2.5 cm  u12=d2+a2 u1=d2+a2=2.52+6.22=6.685 cma=62 \ mm \rightarrow cm=62 / 10 \ cm=6.2 \ cm \ \\ c=3.2 \ \text{cm} \ \\ d=0.25 \ dm \rightarrow cm=0.25 \cdot \ 10 \ cm=2.5 \ cm \ \\ \ \\ u_{1}^2=d^2 + a^2 \ \\ u_{1}=\sqrt{ d^2 + a^2 }=\sqrt{ 2.5^2 + 6.2^2 }=6.685 \ \text{cm}
u22=d2+c2 u2=d2+c2=2.52+3.22=4.061 cmu_{2}^2=d^2 + c^2 \ \\ u_{2}=\sqrt{ d^2 + c^2 }=\sqrt{ 2.5^2 + 3.2^2 }=4.061 \ \text{cm}
b2=d2+(a−c)2 b=d2+(a−c)2=2.52+(6.2−3.2)2=3.905 cmb^2=d^2 + (a-c)^2 \ \\ b=\sqrt{ d^2 + (a-c)^2 }=\sqrt{ 2.5^2 + (6.2-3.2)^2 }=3.905 \ \text{cm}

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