# AM of three numbers

The number 2010 can be written as the sum of 3 consecutive natural numbers. Determine the arithmetic mean of these numbers.

Correct result:

x =  670

#### Solution:

$\ \\ 2010=a + (a+1)+(a+2) \ \\ \ \\ 3a=2007 \ \\ \ \\ a=669 \ \\ \ \\ x=a+1=669+1=670$

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