AM of three numbers

The number 2010 can be written as the sum of 3 consecutive natural numbers. Determine the arithmetic mean of these numbers.

Correct result:

x =  670

Solution:

 2010=a+(a+1)+(a+2)  3a=2007  a=669  x=a+1=669+1=670 \ \\ 2010=a + (a+1)+(a+2) \ \\ \ \\ 3a=2007 \ \\ \ \\ a=669 \ \\ \ \\ x=a+1=669+1=670



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