Rectangle field

The field has a shape of a rectangle having a length of 119 m and a width of 19 m. , How many meters have to shorten its length and increase its width to maintain its area and circumference increased by 24 m?

Correct result:

x =  102 m
y =  114 m

Solution:

119 19=(119x) (19+y) 2(119+19)+24=2 ((119x)+(19+y))  y=x+12  11919=(119x)(19+(x+12))  119 19=(119x) (19+(x+12)) x288x1428=0  a=1;b=88;c=1428 D=b24ac=88241(1428)=13456 D>0  x1,2=b±D2a=88±134562 x1,2=88±1162 x1,2=44±58 x1=102 x2=14   Factored form of the equation:  (x102)(x+14)=0  x=x1=102=102 m

Our quadratic equation calculator calculates it.

y=x+12=102+12=114 a=119x=119102=17 m b=19+y=19+114=133 m  y=114=114 m



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