Ball bearings

One bearing is selected from the shipment of ball bearings. It is known from previous deliveries that the inner bearing radius can be considered a normal N distribution (µ = 0.400, σ2 = 25.10^−6). Calculate the probability that the selected radius will exceed 0.405 for the selected bearing.

Correct answer:

p =  0.1587

Step-by-step explanation:

$$\begin{gathered} \mu =0.400 \\ {\sigma }^2=25\cdot 10^{-6} \\ \sigma =\sqrt{25\cdot 10^{-6}}=0.005 \\ p=N(x>0.405,\mu ,\sigma ) \\ p=0.1587 \end{gathered}$$

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