Two ships

Two ships sailed from Venice - a cargo speed of 10 knots and a ferry speed of 18 knots. At what time will the ferry catch up with the cargo ship if it sailed 10 hours later?

Correct result:

t =  12.5 h

Solution:

$$\begin{gathered} v_1=10\cdot 1.852=18.52\text{ km/h } \\ {v}_2=18\cdot 1.852=33.336\text{ km/h } \\ {s}_1=s_2 \\ {v}_1\cdot (t+10)=v_2\cdot t \\ 18.52\cdot (t+10)=33.336\cdot t \\ 14.816t=185.2 \\ t={\displaystyle \frac{25}{2}}=12.5={\displaystyle \frac{25}{2}}\text{ h}=12.5\text{ h} \end{gathered}$$

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