Ships

At 8:40 the ship set sail at 12 km/h. At 19:10 followed by at 29 km/h sail boat. When sail boat catches up the ship?

How many minutes will catch up took?

Result

hour of catch-up:  2
minute of catch-up:  35
duration of catch-up:  445 min

Solution:

s1=s2 12(t60+Δt)=29t60 Δt=t2t1=19+106084060=0  t=445  min s_1 = s_2 \ \\ 12\cdot ( \dfrac{ t }{60} + \Delta t)=29\cdot \dfrac{ t}{60} \ \\ \Delta t = t_2 - t_1 = 19+ \dfrac{ 10}{ 60} -8 - \dfrac{ 40 }{ 60} = 0 \ \\ \ \\ t = 445 \ \text{ min }



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