Steamer

At 6:40 AM, a steamboat departed from a port at a speed of 12 km/h. At exactly 10:00 AM, a motorboat set off at 42 km/h in the same direction. When will the motorboat catch up with the steamboat?

Result

t = 11:20 hh:mm Wrong answer

Step-by-step explanation:

t1=6:40=6 hr 40 min =6+6040=6.6667 hr6.6667 t2=10 h  v1=12 km/h v2=42 km/h  v1 (tt1)=v2 (tt2) 12 (t6.6666666666667)=42 (t10)  30t=340  t=30340=11.33333333  t=33411.333333=11.33333=11:20 hh:mm



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algebraUnits of physical quantitiesthemes, topicsGrade of the word problem

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