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At 6.40, a cyclist started from the station at a speed of 12 km/h. At exactly 10:00, the car followed him at a speed of 84 km/h. What time does the car catch the cyclist?


t = 10:33 hh:mm Wrong answer

Step-by-step explanation:

t1=66040=6+6040=606 60+40=60360+40=60400=3206.6667 h v1=12 km/h t2=10.00 h v2=84 km/h  s1=s2  v1 (tt1)=v2 (tt2) 12 (t6.6666666666667)=84 (t10)  72t=760  t=72760=10.55555556  t=99510.555556=10.55556=10:33 hh:mm

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