# Tank

The tank bottom has dimensions of 1.5 m and 3 2/6 m. The tank is 459.1 hl of water.

How high is the water surface?

Result

h =  9.182 m

#### Solution:

$V = 459.1 \ hl = 45.91 \ m^3 \ \\ V = abh \ \\ h = \dfrac{ V }{ab} = \dfrac{ 45.91 }{ 1.5 \cdot 3\dfrac{ 2}{ 6} } \ \\ h = 45.91 / 5 \ \\ h = 9.182 \ \text{ m } \ \\$

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