Tank

In the middle of a cylindrical tank with a bottom diameter 251 cm is standing rod which is 13 cm above the water surface. If we bank rod its end reach surface of the water just by the tank wall.

How deep is the tank?

Result

h =  599.28 cm

Solution:

 x2=(251/2)2+(x13)2 0=(251/2)22x13+132  x=612.279 cm h=x13=599.28 cm \ \\ x^2 = (251/2)^2 + (x-13)^2 \ \\ 0 = (251/2)^2 -2 \cdot x \cdot 13 + 13^2 \ \\ \ \\ x = 612.279 \ cm \ \\ h = x-13 = 599.28 \ \text{cm}



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