Tributaries

The pool can be filled with two different tributaries. The first inflow would fill the pool in 18 hours, both in 6 hours. How many hours would the pool filled with a second inflow?

Correct result:

x =  9 h

Solution:

$$\begin{gathered} 6\cdot (1\mathrm{/}18+1\mathrm{/}x)=1 \\ y=1\mathrm{/}x \\ 6\cdot (1\mathrm{/}18+y)=1 \\ 108y=12 \\ y={\displaystyle \frac{1}{9}}\doteq 0.111111 \\ x=1\mathrm{/}y=1\mathrm{/}0.1111=9\text{ h} \end{gathered}$$

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