Tributaries

We can fill the pool with two different tributaries. The first inflow would fill the pool in 18 hours, both in 6 hours. How many hours would the pool fill with a second inflow?

Correct answer:

t₂ =  9 h

Step-by-step explanation:

$$\begin{gathered} t_1=18\text{ h } \\ t=6 \\ t\cdot (1\mathrm{/}{t}_1+1\mathrm{/}{t}_2)=1 \\ t\cdot (t_2\mathrm{/}{t}_1+1)=t_2 \\ 6\cdot (t_2\mathrm{/}18+1)=t_2 \\ 12t_2=108 \\ {t}_2=9=9\text{ h} \end{gathered}$$

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