Octagonal pyramid

Find the volume of a regular octagonal pyramid with height v = 100 and the angle of the side edge with the plane of the base is α = 60°.

Correct answer:

V =  314269.6805

Step-by-step explanation:

v=100 α=60  α1=α=60°=1.0472=π/3 n=8  tanα=v/r  r=v/tan(α1)=100/tan1.047257.735  β=2 n2π=2 82 3.14160.3927 rad  sinβ=x/r  x=r sinβ=57.735 sin0.392722.0942  r2=x2+w2 w=r2x2=57.735222.0942253.3402  S1=2w x=253.3402 22.0942589.2557  S=2 n S1=2 8 589.25579428.0904  V=31 S v=31 9428.0904 100=314269.6805=3.143105

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