Octagonal pyramid

Find the volume of a regular octagonal pyramid with height v = 100 and the angle of the side edge with the base plane is α = 60°.

Final Answer:

V =  314269.6805

Step-by-step explanation:

v=100 α=60  α1=α=60°=1.0472=π/3 n=8  tan α = v/r  r=v/tan(α1)=100/tan1.047257.735  β=2 n2π=2 82 3.14160.3927 rad  sin β  = x / r  x=r sinβ=57.735 sin0.392722.0942  r2 = x2 + w2 w=r2x2=57.735222.0942253.3402  S1=2w x=253.3402 22.0942589.2557  S=2 n S1=2 8 589.25579428.0904  V=31 S v=31 9428.0904 100=314269.68053.143105

Try calculation via our triangle calculator.




Help us improve the example. If you find a mistake, let us know. Thank you!







Tips for related online calculators
See also our right triangle calculator.
Tip: Our volume units converter will help you convert volume units.
See also our trigonometric triangle calculator.

You need to know the following knowledge to solve this word math problem:

algebrasolid geometryplanimetricsgoniometry and trigonometryUnits of physical quantitiesGrade of the word problem

 
We encourage you to watch this tutorial video on this math problem: video1

Related math problems and questions: