Tank and water

Cylindrical tank were poured with 3.5 liters of water. If tank base diameter is 3 dm, how height is water level in?

Result

x =  0.5 dm

Solution:

V=πr2x=π(D/2)2x x=4VπD2=4⋅3.5π32=0.5 dmV = \pi r^2 x = \pi (D/2)^2 x \ \\ x = \dfrac{ 4V}{ \pi D^2 } = \dfrac{ 4 \cdot 3.5 }{ \pi 3^2 } = 0.5 \ \text{dm}

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