# Box of chocolates

In a box of chocolates were 16 candies. Christopher and Luke were distributed:
c) Christopher had three times more sweets than Luke. How many had each boy candies?

a) k =  10
a) l =  6
b) K =  5
b) L =  11
c) x =  12
c) y =  4

### Step-by-step explanation:

k+l=16
k=4+l

k+l = 16
k-l = 4

Row 2 - Row 1 → Row 2
k+l = 16
-2l = -12

l = -12/-2 = 6
k = 16-l = 16-6 = 10

k = 10
l = 6

Our linear equations calculator calculates it.

K+L=16
K=L-6

K+L = 16
K-L = -6

Row 2 - Row 1 → Row 2
K+L = 16
-2L = -22

L = -22/-2 = 11
K = 16-L = 16-11 = 5

K = 5
L = 11

Our linear equations calculator calculates it.

x+y=16
x=3y

x+y=16
x=3·y

x+y = 16
x-3y = 0

Row 2 - Row 1 → Row 2
x+y = 16
-4y = -16

y = -16/-4 = 4
x = 16-y = 16-4 = 12

x = 12
y = 4

Our linear equations calculator calculates it. Did you find an error or inaccuracy? Feel free to write us. Thank you!

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