Box of chocolates

In a box of chocolates were 16 candies. Christopher and Luke were distributed: a) Christopher had about 4 candies over Luke, b) Christopher had about 6 candies less than Luke, c) Christopher had 3 times more sweet than Luke. How many had each boy candies?

Correct answer:

a) k =  10
a) l =  6
b) K =  5
b) L =  11
c) x =  12
c) y =  4

Step-by-step explanation:


k+l=16
k=4+l

k+l = 16
k-l = 4

k = 10
l = 6

Our linear equations calculator calculates it.

K+L=16
K=L-6

K+L = 16
K-L = -6

K = 5
L = 11

Our linear equations calculator calculates it.

x+y=16
x=3y

x+y=16
x=3•y

x+y = 16
x-3y = 0

x = 12
y = 4

Our linear equations calculator calculates it.

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