Box of chocolates

In a box of chocolates was 16 candies.
Christopher and Luke they were distributed:

a) Christopher had about 4 candies over Luke,
b) Christopher had about 6 candies less than Luke,
c) Christopher had 3 times more sweet than Luke.

How many had each boy candies?

Result

a) k =  10
a) l =  6
b) K =  5
b) L =  11
c) x =  12
c) y =  4

Solution:


k+l=16
k=4+l

k+l = 16
k-l = 4

k = 10
l = 6

Calculated by our linear equations calculator.

K+L=16
K=L-6

K+L = 16
K-L = -6

K = 5
L = 11

Calculated by our linear equations calculator.

x+y=16
x=3y

x+y = 16
x-3y = 0

x = 12
y = 4

Calculated by our linear equations calculator.

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To solve this verbal math problem are needed these knowledge from mathematics:

Do you have a linear equation or system of equations and looking for its solution? Or do you have quadratic equation?

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