# Box of chocolates

In a box of chocolates was 16 candies.
Christopher and Luke they were distributed:

c) Christopher had 3 times more sweet than Luke.

How many had each boy candies?

Correct result:

a) k =  10
a) l =  6
b) K =  5
b) L =  11
c) x =  12
c) y =  4

#### Solution:

k+l=16
k=4+l

k+l = 16
k-l = 4

k = 10
l = 6

Our linear equations calculator calculates it.

K+L=16
K=L-6

K+L = 16
K-L = -6

K = 5
L = 11

Our linear equations calculator calculates it.

x+y=16
x=3y

x+y=16
x=3•y

x+y = 16
x-3y = 0

x = 12
y = 4

Our linear equations calculator calculates it. We would be pleased if you find an error in the word problem, spelling mistakes, or inaccuracies and send it to us. Thank you! Tips to related online calculators
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