Box of chocolates

In a box of chocolates were 16 candies. Christopher and Luke shared them:
a) Christopher had four more candies than Luke,
b) Christopher had six fewer candies than Luke,
c) Christopher had three times as many candies as Luke. How many candies did each boy have?

Final Answer:

k =  10
l =  6
K =  5
L =  11
x =  12
y =  4

Step-by-step explanation:

$k=16/2+4/2=10$

$l=16/2-4/2=6$

$K=16/2-6/2=5$

$L=16/2+6/2=11$

$$\begin{gathered} 3y+y=16 \\ 3\cdot y+y=16 \\ 4y=16 \\ y=\frac{16}{4}=4 \\ y=4 \\ x=3\cdot y=3\cdot 4=12 \end{gathered}$$

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