Computer

The computer was purchased 10000,-. Each year, the price of a computer depreciates always the same percentage of the previous year. After four years, the value of the computer is reduced to 1300,- How many percent was depreciated price of the computer each year?

Result

p =  39.95 %

Solution:

10000q4=1300 10000(1+p/100)4=1300 (1+p/100)4=1300/10000  p=100⋅(1−1300/100004)=39.95%10000 q^4 = 1300 \ \\ 10000 (1+p/100)^4 = 1300 \ \\ (1+p/100)^4 = 1300/10000 \ \\ \ \\ p = 100\cdot (1-\sqrt[4]{ 1300/10000 }) = 39.95 \%

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