Computer

The computer was purchased 10000,-. Each year, the price of a computer depreciates always the same percentage of the previous year. After four years, the value of the computer is reduced to 1300,- How many percent was depreciated price of the computer each year?

Correct result:

p =  39.95 %

Solution:

$$\begin{gathered} 10000q^4=1300 \\ 10000(1+p\mathrm{/}100{)}^4=1300 \\ (1+p\mathrm{/}100{)}^4=1300\mathrm{/}10000 \\ p=100\cdot (1-\sqrt[4]{1300\mathrm{/}10000})=39.95\mathrm{\%} \end{gathered}$$

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