Cylinder - basics

Cylinder with base radius r = 45 dm and height h=22 dm. Calculate:

Result

Area of base A1 =  6361.7 dm2
Cylinder volume V =  139958 dm3
Perimeter of base p =  282.7 dm
Area of shell A2 =  6220.4 dm2
Surface area A3 =  18943.8 dm2

Solution:

A1=π⋅452=6361.7 dm2A_1 = \pi \cdot 45^2 = 6361.7 \ \text{dm}^2
V=A1⋅22=139958 dm3V = { A}_1 \cdot 22 = 139958 \ \text{dm}^3
p=2π⋅45=282.7 dmp = 2\pi \cdot 45 = 282.7 \ \text{dm}
A2=p⋅22=6220.4 dm2A_2 = p \cdot 22 = 6220.4 \ \text{dm}^2
A3=A2+2A1=18943.8 dm2A_3 = A _ 2 + 2{ A }_1 = 18943.8 \ \text{dm}^2

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