Shell of cylinder

Calculate the content of shell the 1.6 m height cylinder with a base radius of 0.4 m.

Result

S =  4.021 m2

Solution:

S=1.6⋅ (2π⋅ 0.4)=1.6⋅ (2⋅ 3.1416⋅ 0.4)≐4.0212≐4.021 m2S=1.6 \cdot \ (2 \pi \cdot \ 0.4)=1.6 \cdot \ (2 \cdot \ 3.1416 \cdot \ 0.4) \doteq 4.0212 \doteq 4.021 \ \text{m}^2

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