Medians and sides

Determine the size of a triangle KLM and the size of the medians in the triangle. K=(-5; -6), L=(7; -2), M=(5; 6).

Correct result:

k =  8.2462
l =  15.6205
m =  12.6491
t1 =  13.6015
t2 =  7.2801
t3 =  10.7703

Solution:

x0=−5 y0=−6 x1=7 y1=−2 x2=5 y2=6 k=(x2−x1)2+(y2−y1)2=(5−7)2+(6−(−2))2=2 17=8.2462
l=(x0−x2)2+(y0−y2)2=((−5)−5)2+((−6)−6)2=2 61=15.6205
m=(x0−x1)2+(y0−y1)2=((−5)−7)2+((−6)−(−2))2=4 10=12.6491
a0=(x1+x2)/2=(7+5)/2=6 a1=(y1+y2)/2=((−2)+6)/2=2 b0=(x0+x2)/2=((−5)+5)/2=0 b1=(y0+y2)/2=((−6)+6)/2=0 c0=(x0+x1)/2=((−5)+7)/2=1 c1=(y0+y1)/2=((−6)+(−2))/2=−4 t1=(x0−a0)2+(y0−a1)2=((−5)−6)2+((−6)−2)2=185=13.6015
t2=(x1−b0)2+(y1−b1)2=(7−0)2+((−2)−0)2=53=7.2801
t3=(x2−c0)2+(y2−c1)2=(5−1)2+(6−(−4))2=2 29=10.7703

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